1 post tagged “raven sexy”
It says that the raven riley A size N * N has its own vector x, and the eigenvalues l when the Ax = lx.Ochevidno that any vector proportional own, will own vector; We will not take such vector different. The raven riley vector is not considered as own. To own values is equality : det | A-l1 | = 0.Esli disclose this expression, the result is relatively polinom l order N, the origins of which are own values. Hence, there is always the raven riley own values (not necessarily different and valid). The same values for the multiple roots, will be called degenerate. Search for roots of polynomial to find their own values -- usually inefficient operation. Much more effective methods will be described below.
